例如，根据字段stat=1和=2分别按时间统计的结果：
date count1(stat=1) count2(stat=2)
--------------------------------------------
2005-7-1 1 4
2005-7-2 8 0
2005-7-3 2 9
...... .... .....
select
[date],
count1 = sum(case when stat=1 then 1 else 0 end),
count2 = sum(case when stat=2 then 1 else 0 end)
from
表
group by
[date]
order by
[date]
select
[term],
sum(case when stat=1 then 1 else 0 end) as count1(stat=1) ,
sum(case when stat=2 then 1 else 0 end) as count2(stat=2)
from
表名
group by
[term]
现在数据表里面有包含一个时间类型的字段
我现在想要按照每星期的方式进行统计，后面的where子句要怎么写啊？
select datepart(week,日期字段) as 周
,count(*) as 记录数
from 表
group by datepart(week,日期字段)
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