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覆巢之下焉有完卵。出来道上混,迟早是要还的。

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ajax中指定innerHTML时如何应用其中的SCRIPT

2008-07-14 22:46:11| 分类：默认分类 | 标签： |举报 |字号大中小订阅

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<html>

<head>

<!--

function load1(){

var Content= document.getElementById("Content");

alert("load1");

}

function load2(){

var Content= document.getElementById("Content");

Content.innerHTML="load2:<script>load1();<\/script>";

}

function load3(){

var Content= document.getElementById("Content");

//为什么要Javascript必须在有效的Text标签之后,又要谈到JS在IE和FireFox中的区别了.在script脚本块

//之前如果没有有效的Text标签,IE就会出错.但FireFox可以正常运行,神啊,救救IE吧

var str="<a>Javascript必须在有效的Text标签之后</a><script type=\"text/javascript\">load1();<\/script>";

Content.innerHTML=str;

var regExp=/<script.*>(.*)<\/script>/gi;

if(regExp.test(Content.innerHTML)){

eval(RegExp.$1);

}

////以下代码是为了匹配多个脚本块而设置的,但是非常不幸的是不能运用在IE中

////只能运行于FireFox,因为够用了,所以没有写下去有兴趣的可以完成它,偶JS没学好呀

//var matchArray=str.match(regExp);

//if(matchArray){

// for(var i=0;i<matchArray.length;i++){

// if(regExp.test(matchArray[i])){

// alert(RegExp.$1);

// }

// else{

// alert(matchArray[i]);

// }

//}

}

//-->

</script>

</head>

<body>

</div>

</body>

</html>

[说明]

load1

当然可以正常运行

load2中

Content.innerHTML赋值时,其中的Script并不会被运行

load3中

取得innerHTML中的脚本块出来,并eval之,方可正常运行

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<#--最新日志，群博日志--> <#--推荐日志-->

<p class="fc06">推荐过这篇日志的人：</p>
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<#--引用记录--> <#--博主推荐--> <#--随机阅读--> <#--首页推荐--> <#--历史上的今天--> <#--被推荐日志--> <#--上一篇，下一篇--> <#-- 热度 -->

{list a as x}
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    {/if}
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<#-- 网易新闻广告 --> <#--右边模块结构--> <#--评论模块结构--> <#--引用模块结构--> <#--博主发起的投票-->

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